Answer
$S_6=-105$
Work Step by Step
We need to find:
$\sum_{k=1}^{6}5(-2)^{k-1}$
We see that this is a geometric sequence with $a=5$ and $r=-2$.
We know the partial sum of a geometric sequence is:
$S_n=a_1\frac{1-r^n}{1-r}$
$S_6=5\frac{1-(-2)^{6}}{1-(-2)}=-105$