College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 8, Sequences and Series - Section 8.3 - Geometric Sequences - 8.3 Exercises - Page 615: 16


The sequence is geometric. The common ratio is $r=-\dfrac{1}{3}$.

Work Step by Step

A geometric sequence has a common ratio $r$. The common ratio is multiplied to the current term to get the next term of the sequence. The common ratio is equal to the the quotient of a term and the term before it. Solve for the ratio of each pair of consecutive terms to obtain: $\dfrac{-144}{432} = -\dfrac{1}{3} \\\dfrac{48}{-144}=-\dfrac{1}{3} \\\dfrac{-16}{48} = -\dfrac{1}{3}$ Since the ratio is common to all pairs of consecutive terms, then the sequence is geometric. The common ratio is $r=-\dfrac{1}{3}$.
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