College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 8, Sequences and Series - Section 8.3 - Geometric Sequences - 8.3 Exercises - Page 615: 54

Answer

$341/512$.

Work Step by Step

We know that $2^9=512$. Thus, we have $-1/512$ as the the tenth term of the sequence. The sum of a geometric sequence until $n$ can be obtained by the formula $S_n=a_1(\frac{1-r^n}{1-r})$ where $a_1$ is the first term and $r$ is the common ratio. Hence, here the sum is: $S_{10}=1(\frac{1-(-0.5)^{10}}{1-(-0.5)})=341/512$
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