## College Algebra 7th Edition

Published by Brooks Cole

# Chapter 8, Sequences and Series - Section 8.3 - Geometric Sequences - 8.3 Exercises - Page 615: 45

#### Answer

The first three terms are: $a=1728 \\a_2=1296 \\a_3=972$

#### Work Step by Step

To find the first three terms, the value of the common ratio $r$ is needed. Note that the previous term of a geometric sequence can be found by dividing the common ratio $r$ to the current term. The geometric sequence has: $r=0.75$ $a_4=729$ To find the third term, divide $a_4$ by the common ratio $r$ to obtain: $a_3 = \dfrac{a_4}{r} \\a_3=\dfrac{729}{0.75} \\a_3=972$ To find the second term, divide $a_3$ by the common ratio $r$ to obtain: $a_2 = \dfrac{a_3}{r} \\a_2=\dfrac{972}{0.75} \\a_2=1296$ To find the first term, divide $a_2$ by the common ratio $r$ to obtain: $a = \dfrac{a_2}{r} \\a=\dfrac{1296}{0.75} \\a=1728$

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