College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 8, Sequences and Series - Section 8.1 - Sequences and Summation Notation - 8.1 Exercises: 9


$a_{1}=-1$ $a_{2}=\frac{1}{4}$ $a_{3}=-\frac{1}{9}$ $a_{4}=\frac{1}{16}$ $a_{100}=\frac{1}{10000}$

Work Step by Step

We are given: $a_{n}= \frac{(-1)^{n}}{n^{2}}$ We evaluate: $a_{1}= \frac{(-1)^{1}}{1^{2}}=\frac{-1}{1}=-1$ $a_{2}= \frac{(-1)^{2}}{2^{2}}=\frac{1}{4}$ $a_{3}= \frac{(-1)^{3}}{3^{2}}=-\frac{1}{9}$ $a_{4}= \frac{(-1)^{4}}{4^{2}}=\frac{1}{16}$ $a_{100}= \frac{(-1)^{100}}{100^{2}}=\frac{1}{10000}$
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