Answer
$a_{1}=1$
$a_{2}=3$
$a_{3}=7$
$a_{4}=15$
$a_{5}=31$
Work Step by Step
We are given:
$a_{n}=2a_{n-1}+1$ and $a_{1}=1$
We evaluate:
$a_{2}=2a_{1}+1=2(1)+1=3$
$a_{3}=2a_{2}+1=2(3)+1=7$
$a_{4}=2a_{3}+1=2(7)+1=15$
$a_{5}=2a_{4}+1=2(15)+1=31$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 8, Sequences and Series - Section 8.1 - Sequences and Summation Notation - 8.1 Exercises - Page 600: 17
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