College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 8, Sequences and Series - Section 8.1 - Sequences and Summation Notation - 8.1 Exercises: 16

Answer

$a_{1}=-24$ $a_{2}=-4$ $a_{3}=-\frac{2}{3}$ $a_{4}=-\frac{1}{9}$ $a_{5}=-\frac{1}{54}$

Work Step by Step

We are given: $a_{n}=\frac{a_{n-1}}{6}$ and $a_{1}=-24$ We evaluate: $a_{2}=\frac{a_{1}}{6}=\frac{-24}{6}=-4$ $a_{3}=\frac{a_{2}}{6}=\frac{-4}{6}=-\frac{2}{3}$ $a_{4}=\frac{a_{3}}{6}=\frac{-\frac{2}{3}}{6}=-\frac{2}{3*6}=-\frac{2}{18}=-\frac{1}{9}$ $a_{5}=\frac{a_{4}}{6}=\frac{-\frac{1}{9}}{6}=-\frac{1}{9*6}=-\frac{1}{54}$
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