College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 8, Sequences and Series - Section 8.1 - Sequences and Summation Notation - 8.1 Exercises: 8

Answer

$a_{1}=-\frac{1}{3}$ $a_{2}=\frac{1}{9}$ $a_{3}=-\frac{1}{27}$ $a_{4}=\frac{1}{81}$ $a_{100}=3^{-100}\approx 1.94\times 10^{-48}$

Work Step by Step

We are given: $a_{n}=( \frac{-1}{3})^{n}$ We evaluate: $a_{1}=(\frac{-1}{3})^{1}=-\frac{1}{3}$ $a_{2}=(\frac{-1}{3})^{2}=\frac{1}{9}$ $a_{3}=(\frac{-1}{3})^{3}=-\frac{1}{27}$ $a_{4}=(\frac{-1}{3})^{4}=\frac{1}{81}$ $a_{100}=(\frac{-1}{3})^{100}=3^{-100}\approx 1.94\times 10^{-48}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.