Answer
$\frac{x^2}{9}+\frac{y^2}{13}=1$
Work Step by Step
Major axis is vertical.
Foci: $(0,±c)=(0,±2)$
$c=2$
Minor axis: $Length=2b$
$2b=6$
$b=3$
$a^2=b^2+c^2=3^2+2^2=9+4=13$
$a=\sqrt {13}$
Equation of the ellipse:
$\frac{x^2}{b^2}+\frac{y^2}{a^2}=1$
$\frac{x^2}{3^2}+\frac{y^2}{(\sqrt {13})^2}=1$
$\frac{x^2}{9}+\frac{y^2}{13}=1$
