Answer
The graph of $x^2+2y^2=8$
Work Step by Step
$x^2+2y^2=8$
$\frac{x^2}{8}+\frac{y^2}{4}=1$
$8\gt4$: Major axis is horizontal.
$a^2=8$
$a=2\sqrt 2$
Vertices: $(±2\sqrt 2,0)$
Also, when $x=0$:
$\frac{0^2}{8}+\frac{y^2}{4}=1$
$y^2=4$
$y=±2$
It gives us the endpoints of the minor axis: $(0,±2)$
