Answer
The graph of $x^2+\frac{y^2}{12}=1$
Work Step by Step
$12\gt1$: major axis is vertical.
$a^2=12$
$a=\sqrt {12}$
Vertices: $(0,±\sqrt {12})$
Also, when $y=0$:
$x^2+\frac{0^2}{12}=1$
$x=±1$
It gives us the endpoints of the minor axis: $(±1,0)$
