Answer
Vertices: $(0,\pm 5)$; Major vertical axis length =10
Minor horizontal axis length =8
$r=3$ and Foci:$(0,\pm 3)$
and $e=\dfrac{3}{5}$
Work Step by Step
Write the general form of the equation of an vertical ellipse .
$\dfrac{x^2}{m^2}+\dfrac{y^2}{n^2}=1$
Then, Vertices: $(0,\pm q)$; Major vertical axis length =2p
Minor horizontal axis length =2q and Foci:$(0, \pm r)$ and $r=\sqrt {m^2-n^2}$
Eccentricity $e=\dfrac{r}{p}$
Need to re-arrange the given equation in the form of Equation -A of the ellipse .
$\dfrac{x^2}{(4)^2}+\dfrac{y^2}{(5)^2}=1$
We can see that $m=5 \\n=4$
Thus, we get Vertices: $(0,\pm 5)$; Major vertical axis length =10
Minor horizontal axis length =8
$r=3$ and Foci:$(0,\pm 3)$
and $e=\dfrac{3}{5}$
