Answer
$10^{2.4}$
Work Step by Step
From the definition of decibel level we see that,
$B=10\log \frac{I}{I_0}$,
$\frac{B}{10}=\log \frac{I}{I_0}$,
$10^{\frac{B}{10}}=\frac{I}{I_0}$,
$I=I_0\times 10^{\frac{B}{10}}$,
$I_1=10^{10.6}\times10^{-12}=10^{-2.4}$,
$I_2=I_0\times 10^{\frac{B}{10}}$,
$I_2=10^{12}\times10^{-12}$,
$I_2=1$.
Therefore, the ratio is, $\dfrac{1}{10^{-2.4}}=10^
{2.4}$
