College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Section 4.7 - Logarithmic Scales - 4.7 Exercises - Page 422: 19

Answer

(a). $B=74.914$ (b). $I=10^{-2.5}$ (c).The ratio is $10^{2.5}:3.1$

Work Step by Step

From the definition of decibel level we see that, $B=10\log \frac{I}{I_0}$, (a). $I_0=10^{-12}$, and $I=3.1\times10^{-5}$, $B=10\log \frac{3.1\times10^{-5}}{10^{-12}}$, $B=10(\log 3.1\times10^{7})$, $B=10(\log 3.1 +\log 10^7)$, $B=10(\log 3.1+7)$, $B=74.914$ (b). $B=10\log \frac{I}{I_0}=95$, $\frac{95}{10}=\log I - \log 10^{-12}$, $9.5=\log I +12$, $-2.5=\log I$, $I=10^{-2.5}$ (c). Without earbuds $I=3.1\times10^{-5}$, With earbuds $I=10^{-2.5}$, Therefore the ratio is, $10^{-2.5}:3.1\times10^{-5}=10^{2.5}:3.1$
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