Answer
$6.31$
Work Step by Step
We know that $M=\log\frac{I}{S}$ and thus $10^M=\frac{I}{S}$
Hence, here if $I_1,I_2$ are the intensities, we have:
$I_1=S10^{9.1},I_2=S10^{8.3}$
Hence,
$\frac{I_1}{I_2}=\frac{10^{9.1}}{10^{8.3}}\approx6.31$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 4, Exponential and Logarithmic Functions - Section 4.7 - Logarithmic Scales - 4.7 Exercises - Page 422: 13
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