Answer
$73$ dB
Work Step by Step
We know that $B=10\log\frac{I}{I_0}$
Hence here
$B=10\log\frac{2\cdot10^{-5}}{10^{-12}}\approx73$ dB
Thus, we have a $73~dB$ intensity level.
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.