Answer
Algebraically, we get $x=\pm 4\sqrt{2}$.
Graphically, we get $x\approx \pm 5.6569$.
Work Step by Step
Solve algebraically:
$x^2-32=0$ (Add with 32)
$x^2=32$ (Take the square root)
$x=\pm\sqrt{32}$
$x=\pm 4\sqrt{2}$
$x\approx 5.6569$
Solve graphically:
We sketch the graph of $y=x^2-32$ as shown below.
We compute that the graph intercepts the x-axis at $x=\pm 5.6569$.
So, the solution is $x=\pm 5.6569$.
