Answer
Algebraically, we get $x=-2\sqrt[3]{2}$.
Graphically, we get $x=-2.5198$.
Work Step by Step
Solve algebraically:
$x^3+16=0$ (Substract with 16)
$x^3=-16$ (Take the third root)
$x=\sqrt[3]{-16}$
$x=-\sqrt[3]{16}$
$x=-2\sqrt[3]{2}$
Solve graphically:
We sketch the graph of $y=x^3+16$ as shown below.
In addition, we compute that the graph intercepts the x-axis at $x=-2.5198$.
Then, the solution is $x=-2.5198$.
