Answer
No solution
Work Step by Step
Solve algebraically:
$x^2+3=2x$ (Substract with $2x$)
$x^2-2x+3=0$
Let us check the discriminant.
$D=b^2-4ac=(-2)^2-4\cdot 1\cdot 3=4-12=-8<0$.
Since $D<0$, the equation has no real solution.
Solve graphically:
We sketch the graphs of $y_1=x^2+3$ and $y_2=2x$ as shown below.
Both do not intersect at any point.
So, the equation has no solution.
