College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.9 - Solving Equations and Inequalities Graphically - 1.9 Exercises - Page 158: 13

Answer

Solving algebraically and graphically, we get the solution $x=\pm 2.5$.

Work Step by Step

Solve algebraically: $16x^4=625$ (Substract with 625) $16x^4-625=0$ (Factorize) $(4x^2-25)(4x^2+25)=0$ (Note that $4x^2+25>0$) $4x^2-25=0$ (Factorize) $(2x+5)(2x-5)=0$ $x=-\frac{5}{2}$ or $x=\frac{5}{2}$ $x=-2.5$ or $x=2.5$ Solve graphically: We sketch the graphs of $y_1=16x^4$ and $y_2=625$ as shown below. Both intersect at $x=-2.5$ and $x=2.5$. So, the solution is $x=\pm 2.5$.
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