Answer
$78$
Work Step by Step
$_{n}C_k=\frac{n!}{(n-k)!k!}$
Thus here: $_{13}C_{11}=\frac{13!}{(13-11)!11!}=\frac{13\cdot12}{2\cdot1}=13\cdot6=78$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 8 - Summary, Review, and Test - Review Exercises - Page 790: 75
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