Answer
$\frac{1}{6}$
Work Step by Step
These events are independent so I can find the probability of both happening by multiplying the probability of them happening individually.
We know that $probability=\frac{\text{number of favourable outcomes}}{\text{number of all outcomes}}$
Hence for the first event the probability is: $\frac{2}{6}=\frac{1}{3}$
Hence for the second event the probability is: $\frac{3}{6}=\frac{1}{2}$
Hence the total probability: $\frac{1}{3}\frac{1}{2}=\frac{1}{6}$