Answer
$120$
Work Step by Step
If we want to choose $k$ elements out of $n$ regarding the order, not allowing repetition, we can do this in $_{n}P_k=\frac{n!}{(n-k)!}$ ways.
The order matters here in the runway order, thus we have to use permutations and we choose $5$ planes out of $5$.
Thus the number of possibilities is $_{5}P_{5}=\frac{5!}{(5-5)!}=\frac{5\cdot4\cdot3\cdot2\cdot1}{1}=120$
