College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Summary, Review, and Test - Review Exercises - Page 790: 90

Answer

$\frac{2}{3}$

Work Step by Step

We know that $probability=\frac{\text{number of favourable outcomes}}{\text{number of all outcomes}}$ The total number of possibilities (the number of all outcomes) obviously is $6$ Out of the $6$, there are $4$, that are lower than $3$ or bigger than $4$, thus there are $4$ "good outcomes". Hence the probability here is: $\frac{4}{6}=\frac{2}{3}$
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