Answer
$165$
Work Step by Step
${n \choose k}=\frac{n!}{k!(n-k)!}$ Hence here: ${11 \choose 8}=\frac{11!}{8!(11-8)!}=\frac{11\cdot10\cdot9\cdot8!}{8!3!}=\frac{11\cdot10\cdot9}{3\cdot2\cdot1}=\frac{990}{6}=165$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 8 - Summary, Review, and Test - Review Exercises - Page 790: 62
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