Answer
$418500$
Work Step by Step
The sum of the first $n$ terms of an arithmetic sequence can be obtained by the following formula: $\frac{n(a_1+a_n)}{2},$ where $a_1$ is the first term, $a_n$ is the nth term and $n$ is the number of terms.
The nth term of an arithmetic sequence can be obtained by the following formula: $a_n=a_1+(n-1)d$, where $a_1$ is the first term and $d$ is the common difference.
Hence here: $d=2300,n=10,a_1=31500,a_{10}=31500+(10-1)2300=52200$
Thus the sum:$\frac{10(31500+52200)}{2}=5\cdot83700=418500$
