College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Summary, Review, and Test - Review Exercises - Page 789: 47

Answer

$\frac{4}{3}$.

Work Step by Step

We can see that the ratio of subsequent terms is $-\frac{1}{2}$, thus $r=-\frac{1}{2}$. The sum of an infinte geometric series can be dividing the first term($a_1$) by the difference of $1$ and the common ratio ($r$). So $S=\frac{a_1}{1-r}$. Hence here $S=\frac{2}{1-(-\frac{1}{2})}=\frac{4}{3}$.
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