College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Summary, Review, and Test - Review Exercises - Page 789: 51

Answer

$x=\frac{47}{99}$

Work Step by Step

Let $0.\overline{47}=x$, then $47.\overline{47}=100x$. Thus $47.\overline{47}-0.\overline{47}=100x-x\\47=99x\\x=\frac{47}{99}$
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