College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Summary, Review, and Test - Review Exercises - Page 789: 38

Answer

$128$

Work Step by Step

$a_1=1$ and we can see that the ratio of subsequent terms is $2$, thus $r=2$ The nth term of a geometric series can be obtained by the following formula: $a_n=a_1\cdot r^{n-1}$, where $a_1$ is the first term and $r$ is the common ratio. Hence here: $a_8=1\cdot2^{8-1}=1\cdot128=128$
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