Answer
See below.
Work Step by Step
$a_n=16\cdot(-\frac{1}{2})^{n-1}$ thus
$a_1=16\cdot(-\frac{1}{2})^{1-1}=16\cdot1=16$
$a_2=16\cdot(-\frac{1}{2})^{2-1}=16\cdot-\frac{1}{2}=-8$
$a_3=16\cdot(-\frac{1}{2})^{3-1}=16\cdot\frac{1}{4}=4$
$a_4=16\cdot(-\frac{1}{2})^{4-1}=16\cdot-\frac{1}{8}=-2$
$a_5=16\cdot(-\frac{1}{2})^{5-1}=16\cdot\frac{1}{16}=1$
