College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.6 - Page 768: 30

Answer

The number of choices of pens available in three colors and four writing tips = $3_{{C}{_{1}}}$ . $4_{{C}{_{1}}}$ = 12

Work Step by Step

The number of choices of pens available in three colors and four writing tips = $3_{{C}{_{1}}}$ . $4_{{C}{_{1}}}$ = $\frac{3!}{(3 - 1)! 1!}\times\frac{4!}{(4 - 1)! 1!}$ = $\frac{3!}{2! 1!}\times\frac{4!}{3! 1!}$ = $\frac{3\times2!}{2! .1!}\times\frac{4\times3!}{3! .1!}$ = $3\times4$ = 12
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