College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.6 - Page 768: 24

Answer

1 - $\frac{5_{{P}{_{3}}}}{10_{{P}{_{4}}}}$ = $\frac{83}{84}$

Work Step by Step

1 - $\frac{5_{{P}{_{3}}}}{10_{{P}{_{4}}}}$ = 1 - $\frac{(\frac{5!}{5 - 3!})}{(\frac{10!}{10 - 4!})}$ = 1 - $\frac{(\frac{5\times4\times3\times2!}{2!})}{(\frac{10\times9\times8\times7\times6!}{6!})}$ = 1 - $\frac{5\times4\times3}{10\times9\times8\times7.}$ = 1 - $\frac{1}{84.}$ = $\frac{83}{84}$
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