Answer
$\frac{7_{{P}{_{3}}}}{3!}$ -$7_{{C}{_{3}}}$ = 0
Work Step by Step
$\frac{7_{{P}{_{3}}}}{3!}$ -$7_{{C}{_{3}}}$ = $\frac{(\frac{7!}{(7 - 3)!})}{3!}$ - $\frac{7!}{(7 - 3)!.3!}$ = $\frac{7!}{(7 - 3)!.3!}$ - $\frac{7!}{(7 - 3)!.3!}$ = 0
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.6 - Page 768: 21
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