Answer
1 - $\frac{3_{{P}{_{2}}}}{4_{{P}{_{3}}}}$ = $\frac{3}{4}$
Work Step by Step
1 - $\frac{3_{{P}{_{2}}}}{4_{{P}{_{3}}}}$ = 1 - $\frac{(\frac{3!}{3 - 2!})}{(\frac{4!}{4 - 3!})}$ = 1 - $\frac{(\frac{3!}{1!})}{(\frac{4!}{1!})}$ = 1 - $\frac{3!}{4!.}$ = 1 - $\frac{3!}{4\times3!.}$ = 1 - $\frac{1}{4}$ = $\frac{3}{4}$
