College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.6 - Page 768: 20

Answer

$50_{{C}{_{3}}}$ = 19600

Work Step by Step

This problem has the case of combination only 3 prizes are the same and no need to arrange them, thus we use the formula $n_{{C}{_{r}}}$ = $\frac{n!}{(n - r)!. r!}$ because we have to choose 3 same prizes. We have to choose and distribute 3 same prizes out of 50, then the ways the prizes are to be awarded = $50_{{C}{_{3}}}$ = $\frac{50!}{(50 - 3)!.3!}$ = $\frac{50\times49\times48\times47!}{47!.3\times2\times1 }$ = 19600
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