Answer
80
Work Step by Step
Reading the graphs,
$\left[\begin{array}{lll}
a_{1}=-4 & & b_{1}=4\\
a_{2}=-2 & & b_{2}=2\\
a_{3}=0 & & b_{3}=0\\
a_{4}=2 & & b_{4}=-2\\
a_{5}=4 & & b_{5}=-4
\end{array}\right]$
$\displaystyle \sum_{i=1}^{5}a_{i}^{2}=(-4)^{2}+(-2)^{2}+0^{2}+2^{2}+4^{2}$
$=16+4+0+4+16=40$
$\displaystyle \sum_{i=1}^{5}b_{i}^{2}=4^{2}+2^{2}+0^{2}+(-2)^{2}+(-4)^{2}=$
$=16+4+0+4+16=40$
$\displaystyle \sum_{i=1}^{5}a_{i}^{2}+\sum_{i=1}^{5}b_{i}^{2}=40+40=80$