Answer
0
Work Step by Step
Reading the graphs,
$\left[\begin{array}{lll}
a_{1}=-4 & & b_{1}=4\\
a_{2}=-2 & & b_{2}=2\\
a_{3}=0 & & b_{3}=0\\
a_{4}=2 & & b_{4}=-2\\
a_{5}=4 & & b_{5}=-4
\end{array}\right]$
$\displaystyle \sum_{i=1}^{5}(2a_{i}+b_{i})=$
$=(2(-4)+4)+(2(-2)+2)+(2(0)+0)+(2(2)+(-2))+(2(4)+(-4))$
$=-4+(-2)+0+2+4$
$=0$
