College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.1 - Page 715: 64

Answer

0

Work Step by Step

Reading the graphs, $\left[\begin{array}{lll} a_{1}=-4 & & b_{1}=4\\ a_{2}=-2 & & b_{2}=2\\ a_{3}=0 & & b_{3}=0\\ a_{4}=2 & & b_{4}=-2\\ a_{5}=4 & & b_{5}=-4 \end{array}\right]$ $\displaystyle \sum_{i=1}^{5}(a_{i}+3b_{i})=$ $=(-4+3(4))+(-2+3(2))+(0+3(0))+(2+3(-2))+(4+3(-4))$ $=8+4+0-4-8$ $=0$
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