Answer
0
Work Step by Step
Reading the graphs,
$\left[\begin{array}{lll}
a_{1}=-4 & & b_{1}=4\\
a_{2}=-2 & & b_{2}=2\\
a_{3}=0 & & b_{3}=0\\
a_{4}=2 & & b_{4}=-2\\
a_{5}=4 & & b_{5}=-4
\end{array}\right]$
$\displaystyle \sum_{i=1}^{5}(a_{i}+3b_{i})=$
$=(-4+3(4))+(-2+3(2))+(0+3(0))+(2+3(-2))+(4+3(-4))$
$=8+4+0-4-8$
$=0$