Answer
45
Work Step by Step
Reading the graph,
$a_{1}=-4$
$a_{2}=-2$
$a_{3}=0$
$a_{4}=2$
$a_{5}=4$
$\displaystyle \sum_{i=1}^{5}(a_{i}^{2}+1)=$
$=((-4)^{2}+1)+((-2)^{2}+1)+((0)^{2}+1)+((2)^{2}+1)+((4)^{2}+1)$
$=17+5+1+5+17$
$=45$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 8 - Sequences, Induction, and Probability - Exercise Set 8.1 - Page 715: 61
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