College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Summary, Review, and Test - Review Exercises - Page 512: 83

Answer

$t=7^{th} year$

Work Step by Step

The formula for compound interest for $n$ compounding per year is, $P(1+\frac{r}{n})^{nt}$, whereas $P$ is the initial investment, $r$ is rate, $t$ is time period, $n$ compounding period. $12500(1+\frac{0.065}{4})^{4t} = 20000$, $(1.01625)^{4t} = 1.6$, $4t \log (1.01625) = \log (1.6)$, $t = \frac{\log (1.6)}{4 \log (1.01625)}=7.28942$, $t=7.3$
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