Answer
$x = 2$
Work Step by Step
$\ln (x+4) - \ln (x+1) = \ln x$
$\ln \frac{x+4}{x+1} = \ln x$
$\frac{x+4}{x+1} = x$
$x+4 = x(x+1)$
$x+4 = x^{2} + x$
$x^{2} + x - x - 4 = 0$
$x^{2} - 4 = 0$
$x^{2} = 4$
$x = ±2$
Since $x\ne -2$, then $x = 2$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 4 - Summary, Review, and Test - Review Exercises - Page 512: 78
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