Answer
$x = 5$
Work Step by Step
$\log_2(x+3)+\log_2(x-3) = 4$
$\log_2 (x+3)(x-3) = 4$
$2^{4} = (x+3)(x-3)$
$16 = x(x-3)+3(x-3)$
$16 = x^{2} - 3x + 3x - 9$
$16 = x^{2} - 9$
$x^{2} - 9 - 16 = 0$
$x^{2} - 25 = 0$
$x^{2} = 25$
$x = ±5$
$x \ne -5$, then $x = 5$
