College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Summary, Review, and Test - Review Exercises - Page 512: 77

Answer

No solution.

Work Step by Step

$\log_3(x-1) - \log_3(x+2) = 2$ $\log_3 \frac{x-1}{x+2} = 2$ $3^{2} = \frac{x-1}{x+2}$ $9 = \frac{x-1}{x+2}$ $9(x+2) = x-1$ $9x + 18 = x -1 $ $9x - x = -1 - 18$ $8x = - 19$ $x = \frac{-19}{8}$ No solution.
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