College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Summary, Review, and Test - Review Exercises - Page 512: 75

Answer

$x = e^{3 - \ln 2} $

Work Step by Step

$3 + 4 \ln (2x) = 15$ $4\ln (2x) = 15-3$ $4\ln (2x) = 12$ $\ln (2x) = 3$ $\ln 2 + \ln x = 3$ $\ln x = 3 - \ln 2$ $e^{3 - \ln 2} = x $
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