College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.5 - Page 504: 9

Answer

$144.8$

Work Step by Step

Let t be years after 2010 $A=A_{0}e^{kt }$, and we are given: $ A_{0 }=99.9\quad$ (for t=0 in 2010) $k=0.0095$ So, our model is $A=99.9e^{0.0095t}$ $A=? \quad $when t=40, in 2050, $ A=99.9e^{0.0095(40)}\approx$144.766174354$\approx 144.8$ (million)
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