College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.5 - Page 504: 6


in the year $2024$ (approximately)

Work Step by Step

Take India's model, substitute A=1238 and solve for t: $A=1095.4e^{0.014t}$ $1416=1095.4e^{0.014t}\qquad.../\div 1095.4$ $\displaystyle \frac{1416}{1095.4}=e^{0.014t}\qquad...$ take ln( ) on both sides $\displaystyle \ln\frac{1416}{1095.4}=0.014t\qquad.../\div 0.014$ $ t=\displaystyle \frac{\ln\frac{1416}{1095.4}}{0.014}\approx$18.4021233847$\approx 18$ years ($18$ years after 2006 =$2024$) India will have the population of $1416$ million approximately
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