Answer
334.7
Work Step by Step
Let t be years after 2010
$A=A_{0}e^{kt }$, and we are given:
$ A_{0 }=184.4\quad$ (for t=0 in 2010)
$k=0.0149$
So, our model is
$A=184.4e^{0.0149t}$
$A=? \quad $when t=40, in 2050,
$ A=184.4e^{0.0149(40)}\approx$334.657396374$\approx 334.7$ (million)