Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.5 - Page 504: 10

334.7

Let t be years after 2010 $A=A_{0}e^{kt }$, and we are given: $ A_{0 }=184.4\quad$ (for t=0 in 2010) $k=0.0149$ So, our model is $A=184.4e^{0.0149t}$ $A=? \quad $when t=40, in 2050, $ A=184.4e^{0.0149(40)}\approx$334.657396374$\approx 334.7$ (million)