Answer
8, 4, 2, 1, 0.5 grams, respectively
Work Step by Step
In the half-life period, half of the mass remains
(of the decaying material).
After 10 seconds, half of the initial mass,
$16\displaystyle \cdot\frac{1}{2}=8$ grams
will be present.
After 20 seconds, (another 10 s), there will be
$8\displaystyle \cdot\frac{1}{2}=4$ grams present.
After 30 seconds, (another 10 s), there will be
$4\displaystyle \cdot\frac{1}{2}=2$ grams present.
After 40 seconds (another 10 s), there will be
$2\displaystyle \cdot\frac{1}{2}=1$ grams present.
After 50 seconds(another 10 s),, there will be
$1\displaystyle \cdot\frac{1}{2}=\frac{1}{2}$ gram present.
