Answer
in the year 2015 (approximately)
Work Step by Step
$A=1095.4e^{0.014t}$
$1238==1095.4e^{0.014t}\qquad.../\div 1095.4$
$\displaystyle \frac{1238}{1095.4}=e^{0.014t}\qquad...$ take ln( ) on both sides
$\displaystyle \ln\frac{1238}{1095.4}=0.014t\qquad.../\div 0.014$
$ t=\displaystyle \frac{\ln\frac{1238}{1095.4}}{0.014}\approx$8.80649331259$\approx$ 9 years
(9 years after 2006 =2015)
India will have the population of 1238 million approximately
in the year 2015
