Answer
$Doesn’t$ $make$ $sense$
Work Step by Step
Though both equations can be solved for $x$ by using logarithmic properties, they require different strategies: $$\log_{10}(3x+1) = 5$$ $$10^5 = 3x + 1$$ $$100,000 - 1 = 3x$$ $$\frac{99,999}{3} = 11,111 = x$$ $$VS$$ $$\log_{10}(3x + 1) = \log_{10}5$$ $$\log_{10}(3x+1) - \log_{10}5 = 0$$ $$\log_{10}(\frac{3x+1}{5}) = 0$$ $$10^0 = \frac{3x+1}{5}$$ $$1(5) = 3x + 1$$ $$5 – 1 = 3x$$ $$\frac{4}{3} = x$$
